From our studies of series circuits in the laboratory we found that they have several important characteristics.
Circuit Legend:
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Parallel Circuits Facts:
| Voltage | The voltage is always the same VT = V1 = V2 |
| Current | The sum of all the branch currents (the current through each load) adds up to the total (source) current IT = I1 + I2 |
| Resistance | The Total resistance RT can be calculated in two possible ways:
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| Power | The Total Power PT can be calculated in two possible ways:
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Example:
In the circuit below, find all the unknown quantities:
| GIVEN | FIND | FIND |
| VTotal = VT = 40 V | V2 = ? | RT= ? |
| ITotal = IT= 8 A | V1 = | P1 = ? |
| R2 = 5.0 Ω | I1 = ? | P2 = ? |
| I2= 3 A | R1 = ? | PT = ? |
Solution:
Use Ohm's law for each component. Start with the component where you have two variables out of the three (RT = VT / IT )
(i) Find I1 If I2= 3 A and IT = 8A, then I1 = IT - I2 = 8 A - 3 A = 5 A
(ii) Find R1 R1 = V1 / I1 = 40 V / 5 A = 8.0 Ω
(iii) Find V1 We know that VT = V1 = V2 (In parallel circuits the voltage is always constant)
Therefore V1= VT = 40V(iv) Now we can find R 2
R 2 = V 2 / I 2 = 40V / 3A = 13.3Ω(v) Find the Total Resistance RT
- Method #1 ----- 1/RT = 1/R1 +1/ R2 = 1/ 8 Ω + 1/13.3 Ω = 0.20 Ω
Careful Now ... if 1/RT = 0.20 Ω then, RT = 1/ 0.20 Ω = 5.0 Ω
- Method #2 ------ RT = VT / IT (Ohm's Law)
= 40 V / 8A = 5.0 Ω
You can see that both methods yield the same result(vi) Find P1 P1 = V1 x I1 = 40 V x 5 A = 200 W
This is the power used by R1(vii) Find P2 P2 = V2 x I2 = 40 V x 3 A = 120 W
This is the power used by R2(vii) Find PT PT = VT x IT = 40 V x 8 A = 320 W
This is the total power used by all three resistors together
Or, Alternatively, PT = P1 + P2 = 200 W + 120 W = 320 W
You can see that both methods yield the same results
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